A. Determine the total number of moles of solid sodium hydroxide required to react with 486.00mL of 0.8000M phosphoric acid (H3PO4).
Did I set up the equation correctly?
3NaOH + H3PO4 --> Na3PO4 + 3H20
Then, mol H3PO4(3mol NaOH/1mol H3PO4) = mol NaOH, where mol H3PO4 = (0.8000M)(0.486L)?
B. Determine the concentration of 232.7mL of lead nitrate, Pb(NO3)2 if the sample reacts exactly with 241.0mL of 0.391M potassium iodide (KI).
Equation: Pb(N03)2 + 2KI --> PbI2 + 2KNO3??
so mol PB(NO3)2 = 0.391 M KI *(.241 L KI) (1 mol Pb(NO3)2/ 2 mol KI)
Thanks. Please reply.