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Author Topic: Elimination reaction  (Read 2118 times)

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skp524

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Elimination reaction
« on: January 20, 2012, 08:15:14 AM »
Can anyone please explain why this product is formed instead of any other possible product(s)? http://www.sendspace.com/file/6ze3yf Is that the amine will first attack the most electrophilic carbon , the one "separates" 2 bromine atoms. Alkylated amine is then formed  and it will in turn form a double bond on the previosuly mentioned carbon atom and the one near to this atom and to carbonyl group , i.e. C=C on upper carbon and middle carbon atoms. This is because the delocalization of pi electrons can increase the stability of the product .
« Last Edit: January 20, 2012, 08:45:31 AM by skp524 »
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Honclbrif

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Re: Elimination reaction
« Reply #1 on: January 20, 2012, 09:29:29 AM »
Can you link directly to an image? I'm personally a little leery about downloading files from strange websites.
« Last Edit: January 20, 2012, 10:07:04 AM by Honclbrif »
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orgopete

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Re: Elimination reaction
« Reply #2 on: January 20, 2012, 11:56:55 AM »
I agree with Honclbrif, please attach the image to your post. Click on Additional Options below the edit box, then attach the file. A jpg file will be viewable directly in the forum.
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skp524

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Re: Elimination reaction
« Reply #3 on: January 20, 2012, 11:34:46 PM »
The organic reaction is attached here
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discodermolide

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Re: Elimination reaction
« Reply #4 on: January 21, 2012, 05:30:49 AM »
Quote from: skp524 on January 20, 2012, 11:34:46 PM
The organic reaction is attached here

Look for the two most acidic protons in the SM and you will get your answer.
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