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Topic: vapor pressure of sulfur dioxide  (Read 5755 times)

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Offline orgo814

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vapor pressure of sulfur dioxide
« on: February 16, 2012, 05:23:51 PM »
The vapor pressure off sulfur dioxide is given by the equation:

log(P(torr)) = 8.3186 - 1425.7/T(K)

What is the normal boiling point of SO2 in K?
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Offline sjb

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Re: vapor pressure of sulfur dioxide
« Reply #1 on: February 17, 2012, 04:42:38 AM »
Quote from: butlerw2 on February 16, 2012, 05:23:51 PM
The vapor pressure off sulfur dioxide is given by the equation:

log(P(torr)) = 8.3186 - 1425.7/T(K)

What is the normal boiling point of SO2 in K?

What does "normal" mean here?
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Offline orgo814

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Re: vapor pressure of sulfur dioxide
« Reply #2 on: February 18, 2012, 01:16:56 AM »
I figured it out. Normal means that we assume 1 atmospheric pressure (in this case 760 torr). That gets rid of the two unknowns and therefore it is easy to solve for temperature.
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