Most of the reagent that attacks are molecule itself and does not exist as independent [Eu+] or [Nu-].So does the bond cleavage of the substrate takes after the reagent attaches itself to it or it cleaves before attacking and then attaches itself?
And why do they even have the tendency to attack? How will I know if the reaction will occur or not? And in the example I quoted why will the "X"[The halogen] will let go of its H on attacking?
"Which is a better base: an amine, or Br-?" -- I think amine will be better base because HBr is strong acid,hence Br- weaker conjugate base? Am I correct Sir?
"Which will the H+ be associated with?"-- I don't get this question
And a question sir? A little off topic from this.Like I have questions to arrange the organic compounds in order of their acidity. So how should I solve them? First form the conjugate base and then look for it stability?
So I have to apply inductive, resonance, hyperconjugation . But what to apply when? Our teacher uses sometime inductive to explain it. What's the correct order? I mean what should be my solving algorthim for such questions?
What kind of organic chemistry course are you taking? Most of your questions should have already had the answers written very clearly in the undergraduate organic chemistry textbooks.
When you're dealing with organic reactions, there are several things you must identify correctly before you could solve and understand the reaction.
For example in the reaction of: C
2H
5Br + NH
3 -> C
2H
5NH
3+ Br
-You should ask yourself:
1. Are there any nucleophile? Yes, NH
32. Are there any good leaving group? Yes, Br
3. What kind of reaction will it undergoes? Nucleophile attack electrophile
4. Where is the electrophile? At the carbon where Br is attached to
5. What mechanism could it possibly go? Most possible is SN2 reaction
(If you don't know SN2 reaction, this link will help:
http://en.wikipedia.org/wiki/SN2_reaction)
6. After the nucleophile attack the electrophile, what will happen? C-NH
3+ bond formed and Br
- leave.
7. Where will the Br
- end? If no other base exists, the Br
- countered with C
2H
5NH
3+ to form C
2H
5NH
3+ Br
- salt as final product
In the case of forming secondary and tertiary amine, you should ask yourself:
8. What if there are other base? NH
3 is a stronger base than C
2H
5NH
2, it will abstract the proton of C
2H
5NH
3+, forming NH
4Br salt.
9. What will happen then? C
2H
5NH
2 will be generated
10. Are there any side reaction that will occur? Yes, C
2H
5NH
2 is nucleophile itself....
and so nucleophile attack electrophile....