April 24, 2024, 06:44:20 PM
Forum Rules: Read This Before Posting


Topic: Anyone willing to help interpret this H-NMR spectrum? (annotated pic attached)  (Read 4187 times)

0 Members and 1 Guest are viewing this topic.

Offline janapix

  • Regular Member
  • ***
  • Posts: 17
  • Mole Snacks: +0/-0


I'm just having some issues with this spectrum.
I've attached the work I've done on it so far... could you help me assign the rest of the peaks?
spectrum: http://i317.photobucket.com/albums/mm395/MunsterMunster/University%20stuff/knorrhnmrspechelp.png

ps: This is for my Knorr synthesis lab - I've also had an issue with the final cyclization step... so just in case anyone would like to save me further hours of pain, I've attached that too =D

mechanism:
http://i317.photobucket.com/albums/mm395/MunsterMunster/University%20stuff/finalknorr.png

Offline Dan

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 4716
  • Mole Snacks: +469/-72
  • Gender: Male
  • Organic Chemist
    • My research
This is a little bit tricky to see straight away because you've got some overlapping peaks.

A: NH - I agree
B: chloroform (from the NMR solvent).

That leaves C, D and E.

You've called E a quartet, and assigned this as the methyl groups 8 and 11. This signal is for Me groups 8 and 11, but it is not a quartet, it is two separate signals. Me 8 and 11 are chemically inequivalent, and so will give two separate signals. Each of them couples to an adjacent CH2, so we would expect to see two separate 1:2:1 triplets for methyl groups 8 and 11. Now, in this case these two signals are very close together and overlap slightly.

I will try to explain, you have two triplets: 1:2:1  1:2:1
But they overlap like this: 1:2:1
                                      1:2:1
             So it looks like a 1:3:3:1  quartet, but in reality is not.

The overlapping is nothing other than bad luck.

Hint: Consider this kind of situation when looking at signal C

What splitting patterns would you expect from the H at positions 7, 10, 12 and 13?

Hint: For signal D, you have measured a coupling constant of 21 Hz, which implies you think it's a doublet. 21 Hz is too high for a H-H coupling constant (0-15 is the usual range)...
My research: Google Scholar and Researchgate

Offline discodermolide

  • Chemist
  • Sr. Member
  • *
  • Posts: 5038
  • Mole Snacks: +405/-70
  • Gender: Male
    • My research history
Try running the spectrum again in C6D6 you will get an aromatic induced shift which, with a bit of luck, will separate your signals for you.
Development Chemists do it on Scale, Research Chemists just do it!
My Research History

Offline janapix

  • Regular Member
  • ***
  • Posts: 17
  • Mole Snacks: +0/-0
Absolutely thrilled to wake up to an answer that helped me assign all my peaks =)
Thanks very much Dan!

As for running a new spectrum, I'm still looking forward to running an NMR at all (sigh, undergrad degree...)

Sponsored Links