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Topic: Solubility Product Constant (Basic)  (Read 2116 times)

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Offline nannon27131

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Solubility Product Constant (Basic)
« on: April 08, 2012, 09:35:28 PM »
The question: Find the Ksp of Silver Acetate.

It is based on a lab conducted where copper metal is made to react with 0.1L silver acetate solution (saturated).
The 2 relavent equations are: Cu + 2Ag+--> Cu2+ + 2Ag and
C2H3O2Ag <=> C2H3O2- + Ag+

The mols of Cu reacted was given (9.44 x 10-4)and I used that to find concentration of Ag+ using the first equation, equivalent mol ratios and the formula c=n/v (v=0.1L). I got 0.0189 M.

****I realize Ksp = [Ag+][C2H3O2-] but how do I find molar [C2H3O2]!?

Offline Foobarz

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Re: Solubility Product Constant (Basic)
« Reply #1 on: April 08, 2012, 11:42:21 PM »
Its the same:

From your equation : C2H3O2Ag <=> C2H3O2- + Ag+

We see that [Ag+] and [C2H3O2-] are equivalent at equilibrium, since it is one to one molar ratio.

So in your case (if your value of [Ag+] is correct), Ksp = 0.0189^2, Ksp=3.57*10^-4.



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