Hi Everyone,I have a question regarding isomers. For C8H18 (octane), it is possible to have two methyl branches from the 3rd carbon in (3,3 dimethylhexane) but it is not possible to have the two methyl branches on the second carbon in (2,2 dimethylhexane). I'll leave the link to a picture of all the isomers of C8H18. I just don't get it... since if you attach the two methyl branches on the second carbon it'll still have the same number of hydrogen atoms and it is a different structural formula so I don't see why it is not a valid isomer. Please explain this to me.image linkEdit: link edited
Mitch Andre Garcia's Chemical Forums 2003-Present.
Page created in 0.064 seconds with 24 queries.