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Topic: Displayed formula of 2-methylbutanoic  (Read 4285 times)

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mattg2006

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Displayed formula of 2-methylbutanoic
« on: December 08, 2005, 12:35:48 PM »
Can anyone tell me how to go about working out the Displayed formula of 2-methylbutanoic?

Cheers
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Offline Albert

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Re:Displayed formula of 2-methylbutanoic
« Reply #1 on: December 08, 2005, 12:44:05 PM »
Well, you have only one chiral centre, so you have to draw 2 enantiomers, R and S...if I understand what you want to know.
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mattg2006

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Re:Displayed formula of 2-methylbutanoic
« Reply #2 on: December 08, 2005, 12:53:04 PM »
Sorry but I dont understand those terms. I'm 16 and have just started the course, so I dont know much. Sorry.
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Offline Albert

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Re:Displayed formula of 2-methylbutanoic
« Reply #3 on: December 08, 2005, 01:03:02 PM »
Ok, now I've got it, don't worry.

You have a chain with 4 C-atoms: one of these atoms is the one bonded to the OH group and double-bonded :D to O. This is called  carboxylic group and has the highest priority: that is why it is your 1.
Then you have 3 C: they are 2, 3 and 4. The second (the closest to COOH) is bond to an H-atom and to a methylic group (-CH3).
« Last Edit: December 08, 2005, 01:31:31 PM by Albert »
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