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Author Topic: Reaction of Tetraaminecopper (II) sulfate  (Read 11125 times)

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Mr. Raru

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Reaction of Tetraaminecopper (II) sulfate
« on: December 11, 2005, 03:56:18 AM »

This is from a 1992 AP chem reaction:

An excess of nitric acid solution is added to a solution of tetraaminecopper(II) sulfate.

What is the net ionic equation without balancing?

In class, my teacher said:

H+ + Cu(NH3)4+2 + SO4-2 -----------------------> Cu+2 +NH4+ + HSO4-1

But when I searched online, numerous sources sad:

H+ + Cu(NH3)4+2  -----------------------> Cu+2 +NH4+

Which one is correct? And why?
Since there is excess nitric acid, I understand why my teacher said the hydrogen sulfate ion would form after the ligand was removed, but I am questioning the formation of HSO4-1.
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Alberto_Kravina

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Re:Reaction of Tetraaminecopper (II) sulfate
« Reply #1 on: December 11, 2005, 05:58:35 AM »

Those two reaction equations are not balanced.
I think that the correct reaction equation would be:

[Cu(NH3)4 ]SO4 + 4 HNO3 --------> 4 NH4NO3 + CuSO4

and maybe the copper sulfate reacts with nitric acid to form hydrogen sulfate ions ( could be something like this : CuSO4+HNO3->CuNO3+ + HSO4- sounds a bit weird neh?) ... ???

However, I think that the first reaction is more likely.
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Re:Reaction of Tetraaminecopper (II) sulfate
« Reply #2 on: December 11, 2005, 06:00:35 AM »

I am questioning the formation of HSO4-1.

HNO3 is stronger acid than HSO4-.
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Mr. Raru

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Re:Reaction of Tetraaminecopper (II) sulfate
« Reply #3 on: December 11, 2005, 08:25:37 AM »

hmm... Im not quite sure I follow. Alberto, my equations are net ionic with spectator ions removed and the question did not require balancing. So if I eliminated the spectator ions from your first equation, I would have got my same net ionic equation. My question is would the sulfate ion react with the hydrogen ion to form the bisulfate ion? ???

Quote
HNO3 is stronger acid than HSO4-.
I know this, but how does it affect the formation of HSO4-
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Toutetsu

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #4 on: January 02, 2010, 07:16:45 AM »

Maybe this is just me being weird, but as far as I can tell the NH3 has no ion.

So, this
Quote
NH4NO3
would be a -1.

The one that comes to me is

2H+ + 2NO3- + Cu(NH3)42+ + SO42- -----> Cu(NH3)4(NO3)2 + H2SO4

Going along with that, since the NH3 is not ionized, I don't see any reason why it would change. Also, the only thing that I can find wrong with this is that all of the products are soluble, so the final answer would be "No net reaction".

I happen to be using this problem for a Christmas assignment, and I know that its a complex ion, so the final answer has to have 1+ molecules/ions bonded to a central metal ion.
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Borek

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #5 on: January 02, 2010, 07:27:05 AM »

Maybe this is just me being weird, but as far as I can tell the NH3 has no ion.

NH3 + H+ <-> NH4+
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Toutetsu

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #6 on: January 04, 2010, 04:42:00 AM »

Sorry, I should have said that I see no reason for the NH3 to ionize.
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AWK

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #7 on: January 04, 2010, 06:10:33 AM »

Sorry, I should have said that I see no reason for the NH3 to ionize.
Why - nitric acid is a strong acid, ammonia is a weak base - the should react.

Both reactions given by Mr Raru are correct - the first one concerns sulfate, the second one may concern nitrate for example
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Toutetsu

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #8 on: January 05, 2010, 07:09:17 AM »

Ok. That makes more sense.

The reaction that my teacher finally gave me was

4H+ + Cu(NH3)42+ ------> 4NH4+ + Cu2+

Since both the sulfate and the nitrate are spectators, we ignore them and simplify it down to that.
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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #9 on: January 05, 2010, 07:55:28 PM »

Ok. That makes more sense.

The reaction that my teacher finally gave me was

4H+ + Cu(NH3)42+ ------> 4NH4+ + Cu2+

Since both the sulfate and the nitrate are spectators, we ignore them and simplify it down to that.

Sulfate in strong acids forms hydrogen sulfate!
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Toutetsu

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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #10 on: January 09, 2010, 12:16:47 PM »

Ok. That makes more sense.

The reaction that my teacher finally gave me was

4H+ + Cu(NH3)42+ ------> 4NH4+ + Cu2+

Since both the sulfate and the nitrate are spectators, we ignore them and simplify it down to that.

Sulfate in strong acids forms hydrogen sulfate!

But the SO42- is aqueous on both sides of the reaction, and is therefore ignored.
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Re: Reaction of Tetraaminecopper (II) sulfate
« Reply #11 on: January 10, 2010, 07:56:36 PM »

In the presence of strong acids SO42- form HSO4-
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