C8H8O3 looks correct to me. Let's gather what you know.
Hmm, I don't know much. :p
I've been reading about spectroscopy online, and it's still really confusing to me.
How many carbons are giving the hydrogen absorptions between 6.5-8.0 ppm? How many carbons are left over and how many of them have hydrogens attached? How many hydrogens? What is the peak at 3.9 ppm?
It looks like 3 carbons but apparently there is a doublet at 6.9 ppm and a triplet at 6.8 ppm. So 4 carbons (I thought around 6.8 was a single peak?)
I am also confused why 10.8 ppm is supposed to be OH when it could be OH, COOH, or CHO according to the chart.
3.9 is O-CHx, I'm assuming it's O-CH3.
What is the peak at 1690 cm-1 in the IR??
Looks like C=O
But my answer key says "the following is not thought to be part of the solution
Broad peak at 3200 cm-1: C-H
Broad peak at 1700 cm-1: C=O
Sharp peak at 2900 cm-1: O-H
Sharp peaks around 1600 cm-1: benzene"
What does this mean?