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Author Topic: half reaction of Potassium permanganate  (Read 17750 times)

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half reaction of Potassium permanganate
« on: June 15, 2004, 02:17:49 PM »

Potassium permanganate reacts with sulfuric acid and potassium bromide to form potassium sulfate, manganese(II) sulfate, bromine, and water. Balance this equation using the half-reaction method. The reaction takes place in an acidic solution.
« Last Edit: April 09, 2005, 01:42:03 PM by Mitch »

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Re:half reactions
« Reply #1 on: June 17, 2004, 09:19:02 PM »

first, check your data booklet for the relevant half-equations

(1) MnO4- (aq) + 8H+ (aq)  +5e -> 4H2O (l)  + Mn2+ (aq)

(2) 2Br- (aq) -> Br2 (aq)  + 2e

Equation (1) uses up 5e while Equation (2) uses up 2e. Since the lowest common multiple between 5 and 2 is ten, we ought to apply the mole-multiplier of 2 and 5 respectively on each equation, such that they involve 10e each.

The modfied half equations would be:

2MnO4- (aq) + 16H+ (aq)  +10e -> 8H2O (l)  + 2Mn2+ (aq)

10Br- (aq) -> 5Br2 (aq)  + 10e

Next, combine both modified half-equations to obtain the final chemical equation, ie:

2MnO4- (aq) + 16H+ (aq)  + 10Br- (aq) -> 8H2O (l)  + 2Mn2+ (aq) + 5Br2 (aq)

« Last Edit: June 17, 2004, 09:21:22 PM by geodome »
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