"Remember that the alkyne must be a terminal alkyne and the halide must be primary. More than one combination of terminal alkyne and halide may be possible."
-This is what it says in the solutions manual of my Ochem book.
In the first practice problem, they asked what you'd add to form
So the answer is CH3CH2CH2C≡C with 1. NaNH2 and 2. CH3Br
~OR~ HC≡CCH3 with 1. NaNH2 and 2. CH3CH2CH2Br
But I thought they said only primary halides can be used...?
Encyclopedia Britannica defines an alkyl halide as this: "In a primary alkyl halide, the carbon that bears the halogen is directly bonded to one other carbon, in a secondary alkyl halide to two, and in a tertiary alkyl halide to three." http://i1261.photobucket.com/albums/ii596/lolita56381/primaryhalide.gif
But how come we used a secondary halide in the 2nd possible reaction?
CH3CH2CH2Br is a secondary halide, right?
In the second practice problem, it asks how we can form (CH3)2CHC≡CCH2CH3
So the answer is only one possible reaction: (CH3)2CHC≡CH with 1. NaNH2 and 2. CH3CH2Br
But why can't we also have another possible reaction using HC≡CCH2CH3 with
1. NaNH2 and 2. (CH3)2CHBr ?
Thanks so much for your *delete me*