April 20, 2024, 04:38:57 AM
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Topic: Initial product of a Lewis acid-base reaction involving silver ion and HNO3  (Read 1434 times)

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Offline besjbo

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I'm told equal volumes of NaI and AgNO3 are mixed. Also, Ag+ exists in aqueous solution as [Ag(H2O)2]+. Initially, a yellow precipitate of silver iodide forms. This is [Ag(H2O)(I)], in addition to H2O.

The addition of 5M NH3 (aq) causes the yellow precipitate to dissolve and a clear, colorless solution to result. This is [Ag(H2O)2]+.
The subsequent addition of 5M HNO3 (aq) causes the yellow precipitate identified as silver iodide to reappear in the clear and colorless solution. Now, I am told that "the formula of the initial product from the Lewis acid-base reaction directly involving HNO3 is NH4+."

Why is that? How exactly does ammonium come about from the given mixtures

Also, from all of these reactions, how exactly can I determine the order (in terms of strength) of the three bases (NO3-, NH3, and H2O) with Ag+?

Offline XGen

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The addition of 5M NH3 (aq) causes the yellow precipitate to dissolve and a clear, colorless solution to result. This is [Ag(H2O)2]+.

How did you come to this conclusion?

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