Topic: Question regarding -I (negative inductive effect) producing group . (Read 2574 times)

sankalpmittal · « **on:** January 03, 2013, 09:41:39 AM »

Why is Nitrogen dioxide , a strong -I producing group that fluorine , or chlorine etc ? This must mean that NO₂ is more electronegative that halogens also , but why is it so ? Is it due to resonance ? Or due to the fact that its formed from a coordinate compound HNO₃ ?

Please Help !!

Thanks in advance...

sankalpmittal · « **Reply #1 on:** January 06, 2013, 01:23:58 PM »

Quote from: sankalpmittal on January 03, 2013, 09:41:39 AM

Why is Nitrogen dioxide , a strong -I producing group that fluorine , or chlorine etc ? This must mean that NO₂ is more electronegative that halogens also , but why is it so ? Is it due to resonance ? Or due to the fact that its formed from a coordinate compound HNO₃ ?

Please Help !!

Thanks in advance...

I restate this question in the quote.

Anyone ? Can anyone help here ? This question is in my mind for several weeks !

ashmus · « **Reply #2 on:** January 06, 2013, 04:57:44 PM »

Think of the formal charges associated with the nitro group.

sankalpmittal · « **Reply #3 on:** January 07, 2013, 02:08:20 PM »

Quote from: ashmus on January 06, 2013, 04:57:44 PM

Think of the formal charges associated with the nitro group.

Well due to -R or negative mesomeric effect , or resonance , formal charge of +1 is on the nitro group. Right ? Is this the reason for my question ?

Topic: Question regarding -I (negative inductive effect) producing group . (Read 2574 times)

sankalpmittal

Question regarding -I (negative inductive effect) producing group .

sankalpmittal

Re: Question regarding -I (negative inductive effect) producing group .

ashmus

Re: Question regarding -I (negative inductive effect) producing group .

sankalpmittal

Re: Question regarding -I (negative inductive effect) producing group .

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