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Author Topic: Equilibrium  (Read 1048 times)

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« on: February 25, 2013, 04:09:48 AM »

Hi, I have this question in my text book that I don't understand how to solve.

We have this CO(g) + H2O(g) <=> CO2(g) + H2(g), and in a jar with constant(?) volume we add 0,7 mol CO, 0,6 mol H2O and 0,1 mol of CO2. When the jar has equilibrium there is 0,5 mols of CO2.

A) Calculate the equilibrium constant.
I got that part it was easy, Equilbrium constant = 3,3

B) How much substance of water vapor do we need to add in the equilibrium, for the jar to contain 0,5 mol of H2 in the new equilibrium state.

Sorry for my bad English.


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Re: Equilibrium
« Reply #1 on: February 26, 2013, 01:51:36 AM »

Try to develop new equation. The value of hydrogen is known. The others you have to express with x. You get a square equation.


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