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Topic: Chemistry Equlibrium Help  (Read 2326 times)

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Offline HowdoIdo

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Chemistry Equlibrium Help
« on: February 25, 2013, 06:48:21 PM »
These are the questions I am having trouble with, you do not need to answer all but any help is greatly appreciated. Thanks!


1) N2(g) + 3H2(g) <-----> 2NH3(g) + energy

The reaction shown took place at 570 Kelvin in a 1.0 liter container. Thee were the concentrations at equilibrium:
[NH3]=.20mol/L
[N2]=.50mol/L
[H2]=.20mol/L

a) At equilibrium, the size of the container is increased. How will this change affect the direction of the reaction, and how will this affect the concetration of NH3(g)?

b) At the given temperacture, 20% of the NH3(g) moles present were removed from the container.
When the equilibrium re-establishes, what will be the new concentration of N2(g) and H2(g)?


2. At equilibrium, the pressure of the gases is as follows: oxygen=1.1 atm Nitrogen(IV)oxide=4.4atm

a) calculate the Kp value

b)Calculate the keq value

c) Examine the Keq value. Based on the magnitude of the Keq value, in what direction is the reaction shifted?

d) To shift the reaction opposite to your response in question C, name a specific reaction that could be taken. There is more than one possible answer.



For the record, these are only a small fraction of my entire workload so I am not just asking someone to do my homework, I really need help. thanks!

Offline HowdoIdo

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Chemistry Equlibrium Multiple Choice
« Reply #1 on: February 25, 2013, 07:24:47 PM »
1) Examine the reaction: 2HI(g) + Cl2(g) <----> 2HCL(g) + I2(g) + energy
At equilibrium which of the following actions will serve to increase the number of moles of iodine present?

a) Increase volume of container but same temp
b) Decrease volume of container but keep temp
c) Add a mole of Helium gas to the container
d) Increase the temperature of container but keeping container size same
e) Decrease the temperature of container but keeping size same

2) Examine the reaction: Br2(g) + I2(g) <----> 2IBr(g)
At 150 degrees C, the Keq value for this reaction is 300. At equlibrium, the pressure of the IBr(g) compound was recorded 3 atm. Which of the following could be the pressures of the Br2(g) and I2(g) respectively?

a).1 and .3 atm
b) .3 and 1 atm
c) 1 and 1 atm
d) 1 and 3 atm
e) 3 and 3 atm

3) 4.8 grams of carbon dioxide gas are pumped into a sealed 250ml size glass container. What is the gas concentration?

a) .27
b)  1.82
c) .44
d) .03
e) .85

4) A reaction at equlilbrium is exothermic. Which of the following actions could result in shifting the reaction to the left?

a) increasing one of the products
b) cooling the reaction down
c) increasing one of the reactants
d) increasing two of the reactants
e) decreasing or removing one of the products

5) Examine this reaction: 3A(s) + 2B(g) <----> 8C(g) + 4D(s)
In the Keq expression which substances will not be included?

a) A
b) B
c) C and D
d) A and C
e) D only
I thought it would have been A and D but I am not sure since it is not a given option

6) In the previous question (#5) when converting the Keq value to a kp value, the value of the exponential power known as "n" will be reported as:

a) 7
b) 3
c) 10
d) 6
e) 5

Offline Dan

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Re: Chemistry Equlibrium Help
« Reply #2 on: February 26, 2013, 02:59:44 AM »
You must show you have attempted the question, this is a Forum Rule.
My research: Google Scholar and Researchgate

Offline Dan

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Re: Chemistry Equlibrium Multiple Choice
« Reply #3 on: February 26, 2013, 03:00:46 AM »
You must show you have attempted the questions, this is a Forum Rule.
My research: Google Scholar and Researchgate

Offline Arkcon

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Re: Chemistry Equlibrium Help
« Reply #4 on: February 26, 2013, 07:27:13 AM »
Hi there, I've merged your two similar topics.  We'd like to see your attempts.  You've asked over a dozen questions, when you consider the multiple parts of each question, even if this is "only a portion of your workload."  Try to show us the reasoning you'd use for one part of one question.  Then we can help you solve a part you're having trouble with.  Then you can solve the rest, maybe with help on one part that you're stuck on.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

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