[xkiwiix]

A 0.120 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.18° in a 1-dm sample container. The molar mass of the compound is 126.0 g/mol.

What is the observed rotation of 100 mL of solution that contains 0.01 mole of D and 0.005 mole of L? Assume a 1-dm path length

[Borek]

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[xkiwiix]

I did 0.01- 005 moles = 0.005 mol of excess D.

(0.005 mol/100 ml) * (126g/mol) = 0.63 g/ml

0.63 g/ml * 1 dm

The specific rotation of D is 11.9 degrees
so is the answer 11.9 *0.63?

[xkiwiix]

I mean 0.0063 * 11.9

[xkiwiix]

Nevermind. I got it. Thanks