I have been given the formula for Iron(III) Oxide (Fe2O3) and have been asked to calculate how many moles are present in 24.6g of the compound whilst working out how many moles of Fe are present in this amount.
I have calculated the mole of Fe2O3 at 0.154 mol,
M= (Fe2O3), M= 2(55.8 ) + 3(16.0)
m = 24.6, M = 159.6, n = ? so, n = m/M, 24.6/159.6 = 0.154mol
I cannot for the life of me grasp how to find out the mol of Fe in 24.6g this compound.
Do I divide the mol of Iron by the weight of the compound? Convert it to a percentage?
Any help would be greatly appreciated