How do you do the last part? (Determine the number of Al13-Keggin ions produced by the reaction.)
Also, is my interpretation of the reaction correct - we are mixing two solids, which will produce water, as well as CO2 gas which escapes, but the water should then dissolve the Al13-Keggin ions (produced originally as part of a solid crystal with chloride anions) along with dissolved ammonium and chloride.