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Topic: Acetic Acid Dissociation Contant calculation question  (Read 10543 times)

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sarahjane

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Acetic Acid Dissociation Contant calculation question
« on: March 18, 2004, 07:12:35 PM »
a 0.01M solution of acetic acid is 4.17% ionised.calculate the dissociation constant of acetic acid?????how do you do this??????






Edit: Editied subject title to help with indexing. Mitch
« Last Edit: March 19, 2004, 05:55:45 AM by Mitch »
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Offline Donaldson Tan

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Re:hey im confused
« Reply #1 on: March 19, 2004, 05:44:04 AM »
The degree of dissociation is 4.17%.

So Ka
= [H+][Acetate]/[Undissociated Acetic Acid]
= (0.0417x0.01)(0.0417x0.01)/[(1 - 0.0417)x0.01]
= (0.0417)(0.0417)(0.01)/0.9583
= 1.81 X 10^(-5)
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