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Topic: Using Nitric Acid to Extract Copper from Ore  (Read 3373 times)

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Offline mkmyers45

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Using Nitric Acid to Extract Copper from Ore
« on: April 15, 2014, 01:00:02 PM »
Approximately how much nitric acid is needed to dissolve 1 tonne of copper before it becomes ineffective?

concentrated nitric acid 70% by weight

or

concentrated nitric acid 98% by weight

Offline mkmyers45

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Small Volume,Lenght and Breath problem
« Reply #1 on: April 15, 2014, 01:14:09 PM »

What will the volume,lenght, breath and width of a glass container that will hold 1 tonne of powdered rock assuming its density is 8.8g/cm3?

What if 1000l of HNO3 is also included? What will be the volume and dimensions?

Offline Borek

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Re: Using Nitric Acid to Extract Copper from Ore
« Reply #2 on: April 15, 2014, 01:30:01 PM »
You have to show your attempts at solving the question to receive help. This is a forum policy.

It wouldn't hurt if the question was making sense, it doesn't as worded.
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Offline Borek

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Re: Small Volume,Lenght and Breath problem
« Reply #3 on: April 15, 2014, 01:30:26 PM »
You have to show your attempts at solving the question to receive help. This is a forum policy.
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Offline Arkcon

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Re: Using Nitric Acid to Extract Copper from Ore
« Reply #4 on: April 15, 2014, 07:29:02 PM »
I hope you don't mind, mkmyers45:, that I merged your two posts.  You seem to be asking similar questions, and I hope having them together gives you a chance to ask more specific questions, and maybe show a little work, so we can learn your thought process.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline mkmyers45

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Re: Using Nitric Acid to Extract Copper from Ore
« Reply #5 on: April 16, 2014, 11:40:00 AM »
Approximately how much nitric acid is needed to dissolve 1 tonne of copper before it becomes ineffective?

concentrated nitric acid 70% by weight

or

concentrated nitric acid 98% by weight

This is what i tried:

for the

1,000,000 g in a tonne

Molar mass Cu = 63.5g/mol

1,000,000/63.5 = 15748.03 mol

Balanced equation:

Cu + 4 HNO3 → Cu(NO3)2 + 2 H2O + 2 NO2

1mol Cu reacts with 4mol HNO3

You have xmol HNO3, which will react with 15748.03 mol Cu

15748.03 * 4 = 62992.13 mol

Molar mass HNO3 = 63g/mol

xg HNO3 = x/63 = 62992.13 mol HNO3

 62992.13 * 63 = 3,968,503.94g HNO3 needed?

3968.50kg..

Am i correct?

Offline mkmyers45

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Re: Small Volume,Lenght and Breath problem
« Reply #6 on: April 16, 2014, 11:40:31 AM »

What will the volume,lenght, breath and width of a glass container that will hold 1 tonne of powdered rock assuming its density is 8.8g/cm3?

What if 1000l of HNO3 is also included? What will be the volume and dimensions?

I have no idea how to go about solving this one....

Offline Borek

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Re: Using Nitric Acid to Extract Copper from Ore
« Reply #7 on: April 16, 2014, 04:17:02 PM »
3968.50kg..

Am i correct?

Looks OK to me. Now you need to find how much solution of a given (say 70%) concentration contains this amount of acid:

3968 kg = 0.7*mass of the solution
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