[elco1980]

Hello, everyone,
  I am a student in college trying to figure out a question which is giving me alot of trouble.  I tried and tried and keep getting the wrong answer I am wondering if anyone has a solution they can post to this qeustion below.  If you do that would be most appreciated!,

Question is:

2. A 0.6000 g sample of K2CO3 (138.2055 g/mol) is dissolved in enough water to make 200.0 mL of solution A. A 20.00 mL aliquot of solution A is taken and put into an Erlenmeyer flask. To the flask is added 20.00 mL of 0.1700 M HCl:

K2CO3(aq) + 2HCl(aq)2KCl(aq) + H2O(l) + CO2(g)
 
The resulting solution is then titrated with 0.1048 M NaOH.
 
NaOH(aq) + HCl(aq) H2O(l) + NaCl(aq)
 
How many mL of NaOH are used? (Answer: 24.16)


Thanks for your *delete me*
elco

[Borek]

Show your calculations.