[kdejffrhj]

Ok I am French, so in our french system, if you fail an exam, you can do it in the summer, I failed Chemistry and also 5 other subjects, Chemistry teacher was nice enough to give me a homework instead of an exam, the due is in three days, I am too busy studying other stuff that needs a lot of memorizing like psychology. I have been looking for help since morning and yet to find someone to take me out of my misery 


So here is it, find Equilibrium Constant Expression http://oi61.tinypic.com/fxwf0h.jpg (I dont know how to add a picture)

[Ben Bob2]

There's an easy formula to follow for writing equilibrium expressions.
http://www.chemguide.co.uk/physical/equilibria/kc.html

This page is a good place to start, and includes several worked-out examples.

[Arkcon]

I attached the image for you.  Briefly, however, what you're asking for isn't what we do here.  We want to help you learn, to help yourself.  Your badly scanned image of 6 reactions shows no sign of the constants or values needed to solve these problems, and we have rules that you must at least try to solve them.  I'd direct you to the rules, but you've said nothing except the same thing three or four times -- that you don't want to even try.  You may be out of luck with our forum here.

[Ben Bob2]

[...]Your badly scanned image of 6 reactions shows no sign of the constants or values needed to solve these problems[...]

To avoid confusing the user: to solve and equilibrium expression would require said values, but to "find" it (as the user states) would simply mean to write it out as below, correct?   

[Wrynn]

I understand the desperation and the will to success with all subjects but why did you leave chemistry as the last one to do and didn't even try to understand? Why do you think it's less important? It's okay to ask for help, it's awesome even. It's great to ask for help with understanding but it's not quite cool to ask others to do something for you totally 

[Vidya]

Ok Let me help you insolvingthis :Read it carefully and apply it on all reactions.
General reaction:
aA (g) + bB(aq)-----> cC(aq) +dD(aq)
Keq=[C]^c[D]^d/ [A]^a[ B]^b
so Keq =
   product of the concentrations of the product raised to their coefficient in the balanced reaction/         
  product of the concentrations of the reactant raised to their coefficient in the balanced reaction
Now do not include solids and pure liquids like pure water
CaCO3(s) <.> CaO(s) + CO2(g)
Keq = [CO2] solids are not included
I am sure you can answer all of them as it is now like mathematics.