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Topic: Grignard reagent in dihaloaryl  (Read 2141 times)

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Offline insertwittyname

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Grignard reagent in dihaloaryl
« on: November 21, 2014, 09:59:10 AM »
in c1cc(cc(c1)Br)Cl what grignard reagent will be formed? the one with Br or with Cl? I'm guessing that since a radical formation is involved and Br radical is more stable, the Grignard reagent with Br should be preferentially formed. Would this be correct?

Offline Hunter2

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Re: Grignard reagent in dihaloaryl
« Reply #1 on: November 21, 2014, 10:16:54 AM »
I think there will be not much difference. Both halogenes create Grignard.

Offline Altered State

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Re: Grignard reagent in dihaloaryl
« Reply #2 on: November 21, 2014, 10:21:17 AM »
I think there will be not much difference. Both halogenes create Grignard.

+1, you will need to use other starting material or substitute one of these halogens by a non-reactive group with Mg

Offline discodermolide

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Re: Grignard reagent in dihaloaryl
« Reply #3 on: November 21, 2014, 11:07:05 AM »
This compound,
ClC1=CC=C(Br)C=C1
forms the Grignard selectively at the bromine's position.
You have the meta compound so I think there will be a good chance that the Br will exchange.

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Offline OrgXemProf

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Re: Grignard reagent in dihaloaryl
« Reply #4 on: November 21, 2014, 11:57:13 AM »
Selective LiCl mediated direct insertion of Mg into the C-Br bond in m-bromochlorobenzene has been reported.

See Entry #3, Table 1, page 19 in: Fabian Michel Piller, LiCl-Mediated Direct Insertion of Magnesium Into Aryl, Heteroaryl and Benzylic Halides. Regio- and Chemoselective Synthesis of 5-Membered Ring Heterocycles. PhD dissertation, Ludwig-Maximilians-Universität München, 2010. The dissertation (pdf file) can be found online c/o http://edoc.ub.uni-muenchen.de/11412/2/Piller_Fabian_Michel.pdf

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