Hey guys,
I hope this is the correct place to post this question, if not I apologize!
If someone can help me out by providing the necessary steps and or point me in the right direction on how to answer this question that would be a great help. Im a bit lost on where to even begin.
"Soluble phosphorus (P) in water is regarded as a nutrient. Typically, P in wastewater exists in the form of HPO42-. It should be removed from wastewater before it is discharged into natural water systems. In wastewater treatment plants, precipitation is a frequently used method to remove P from wastewater. In the precipitation, a coagulant (e.g. FeCl3) is added to transform soluble P to insoluble chemicals (precipitates), as shown below.
FeCl3 + HPO42- = FePO4 (down arrow) + H+ + 3Cl-
These precipitates can be easily removed from water through gravity sedimentation. As a result, the effluent is P-free.
If a wastewater has 8 mg/L HPO42-, what amount (mg/L) of FeCl3 should be added to completely remove it?"