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Topic: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....  (Read 2216 times)

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Offline anna.kolinski

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What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
« on: January 26, 2015, 06:07:47 PM »
Does anybody know what the nuclear spin, I, of Mo(V) and Fe(IV) is?

I'm trying to work out the number of lines that 2nI+1 gives, but the main isotopes have an I = 0 I think (but I'm not sure).

Also, if the main isotopes give I=0, can it still be worked out for the less common isotopes?

Thanks
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Offline Babcock_Hall

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Re: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
« Reply #1 on: January 26, 2015, 06:22:27 PM »
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Offline Enthalpy

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Re: What is the nuclear spin (I) of Mo(V) and Fe(IV)? For NMR splitting....
« Reply #2 on: January 28, 2015, 10:09:06 AM »
Also there, section "isotopes":

http://www.webelements.com/iron/
only 57Fe with 2.1% natural abundence has spin 1/2

http://www.webelements.com/molybdenum/
only 95Mo (15.9%) and 97Mo (9.6%) have spin 5/2.
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