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Topic: O-Chem And IR  (Read 3127 times)

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Offline lrisNil

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O-Chem And IR
« on: February 14, 2015, 09:19:03 PM »
The treatment of acetal A with aqueous acid initially produces unstable compound B, which has a band in its IR spectrum at ~1730 cm–1. However, this compound is only stable at very low temperatures. At room temperature, it reacts to form compound C. The IR spectrum of compound C is does NOT have a band between 1600–1800 cm–1.

Suggest reasonable structures for compounds B and C , and use arrows to show the detailed mechanism for the formation of B from A and for the formation of C from B.

Any help appreciated, thank you.
Iris Lin

Offline billnotgatez

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Re: O-Chem And IR
« Reply #1 on: February 14, 2015, 10:01:25 PM »
Just dumping homework questions here is not how we work here
You have to show your attempts at solving the question to receive help.
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Offline OrgXemProf

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Re: O-Chem And IR
« Reply #2 on: February 17, 2015, 10:24:14 AM »
1. What do you know about the reaction of acetals with aqueous acid?

2. You may recall that in aqueous solution the open-chain form of glucose is in equilibrium with various hemiacetal structures.

Hope the foregoing proves useful.

Offline chr147

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Re: O-Chem And IR
« Reply #3 on: February 19, 2015, 10:58:48 PM »
I've been doing some work on this question and could use a bit of assistance. I've realized that the acid conditions will remove the protecting group, leaving a ketone. Im thinking that the OH group attached to the molecule will result in an intramolecular reaction, rather than the diol reacting with the carbonyl. Would this be correct logic?

Offline lrisNil

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Re: O-Chem And IR
« Reply #4 on: February 20, 2015, 01:54:34 AM »
When it say "aqueous acid" does that just mean HCl?

So I think I should attack the HCl with the lone pairs on the OH, so that results in OH+ (H2O?!) and Cl-

is that correct, I'm confused..!  :-*
Iris Lin

Offline chr147

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Re: O-Chem And IR
« Reply #5 on: February 20, 2015, 02:31:13 AM »
HCl and water, or H3O+

No i think it removes the protecting group instead, thats gonna bring back a carbonyl group.

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