In a class test. I need to find out the structural formula of a compound with providing the empirical formula (C5 H10 O), IR spect, NMR spect and mass spect.
The answer is 3-methylbutanal.
In NMR sepct, there should be 4 signals. The aldehydic proton has a chemical shift around 9. However, there is no spin-spin coupling between aldehydic proton and methylene protons (nearby protons).
Theorectically, the signal of aldehydic proton should be present as triplet and the methylene protons is also triplet (another methine proton just next to them).
In this spect, the signal of aldehydic proton is singlet while the methylene protons is doublet. An explanation from someone is that, there is oxygen affect that proton. But I don't think this case is as same as the high concentrated / pure alcohol which gives no coupling and the effect of magnetic anistropy by C=O double bond only reinforce the applied magnetic field that the proton feels.
The answer 3-methylbutanal is correct and the NMR spect is made by real experiment. So, how to explain it?