[Ciubba]

A 5.00 gram sample of pure nitric acid is dissolved in 1.00 liter of water in a calorimeter that has a TOTAL heat capacity of 5.16 kJ/K. The temperature increases by .511 K. Calculate the molar heat of solution of nitric acid in water

ΔH=5.16*.511=2.637 kJ. The molar heat capacity should be C=[2.637 kJ]/[(.511 K) * (.07937 mol)]=65 [kJ] /[mol K]. However, the book lists the answer as being 33.3 kJ/ mol K, which I can get if I omit the .511 from my "C=" calculation. Am I right or is the book?

[mjc123]

Read the question. It asks for molar heat of solution, not molar heat capacity. What are the units? (Did the book really say 33.3 kJ/mol K?)