My book lists the following reaction:
+Br
2, all in a methanol solvent
I'm not sure I understand the product. Wouldn't
be a more likely product? If there are no acids involved, I don't see that methanol could act as an electrophile, so one of the bromine must be an electrophile. Then, either the bromide ion or methanol could act as a nucleophile for the newly formed R-bromonium complex, with methanol being more likely as its present in larger concentrations.