April 25, 2024, 04:37:46 PM
Forum Rules: Read This Before Posting


Topic: Nitrile unde swern oxidation conditions. Where does the oxygen come from?  (Read 2740 times)

0 Members and 1 Guest are viewing this topic.

Offline Berbik83

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Reading through a patent on the synthesis of the 1,3-diol part of statins, I found they transform a terminal CN group to an aldehyde. I know you can reduce the nitrile to give aldehydes by several methods but since the molecules has an ester group they don't want to risk the reduction of the ester.
They use oxalyl chloride and dmso in DCM and then Et3N classic Swern oxidation conditions but can't figure out how that works...

Any thoughts where the oxygen might come from? would it go through the intermediate I draw?

Thanks

Offline Berbik83

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Re-reading and re-thinking I guess the oxygen comes from the work up which is dissolving in water. So then I guess you have to form an imine but how?

Offline Dan

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 4716
  • Mole Snacks: +469/-72
  • Gender: Male
  • Organic Chemist
    • My research
Doing a reduction under Swern oxidation conditions looks odd...

Can you post the patent number and the page?
My research: Google Scholar and Researchgate

Offline Berbik83

  • New Member
  • **
  • Posts: 5
  • Mole Snacks: +0/-0
Never mind Dan. Mistake on the patent, in a later correction the oxidation occurs on a terminal alcohol instead of a terminal nitrile...
Thanks anyway.

Sponsored Links