Fe
3+ + Y
-4 FeY
- K
f=1.3X10
25Fe
2+ + Y
+4 FeY
2- K
f=2.1x10
14Calculate the E° for the process
FeY
- + e
- FeY
2- The answer is said to be 0.13 V.
My attempt since, the half reaction for the following is
Fe
3+ + e
- Fe
2+ E°= +0.77 V
Fe
2+ + e
- Fe
(s) E°= - 0.44 V
E
1 = 0.77- (RT/Fn)ln 1/Kf
E
1 = 0.77 - 0.0257/(3)(ln 1/ 1.3X10
25) I put three here cuz there's 3 electrons to form Fe(s)
E
1 = 1.27 V
E
2 = -0.44- (RT/Fn)ln 1/Kf
E
2 =-0.44- 0.0257/(2)(ln 1/2.1x10
14) put three here cuz there's 2 electrons to form Fe(s)
E
2 = -0.0162 V
If add or substract this answers I will still not get 0.13 V please help me
DO I still have to use Nert's Equation ?