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Author Topic: Find the pH of a 0.000100 M solution of HOBr?  (Read 4100 times)

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merced

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Find the pH of a 0.000100 M solution of HOBr?
« on: April 25, 2006, 05:48:12 PM »

Find the pH of a 0.000100 M solution of HOBr.

Given: Ka = 2.0 * 10-9

Using a RICE table, Ka = [OBr-][H3O+] / [HOBr]

Let [OBr-] = [H3O+] = x

I got the 2nd degree polynomial: 0 = x2 + 2.0 * 10-9 x - 2.0 * 10-13
Solving for x, I get: x = 4.462 * 10-7 = [H3O+]

Then I find that the pH = 6.350.

The answer supposedly has a pH of 6.262.  What did I do wrong?
« Last Edit: April 30, 2006, 02:23:48 PM by Mitch »
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AWK

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Re: find the pH of...
« Reply #1 on: April 25, 2006, 08:34:19 PM »

Try to include an auto-dissociation of water to your calculations. This leads to a cubic equation.
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Borek

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Re: find the pH of...
« Reply #2 on: April 25, 2006, 09:35:07 PM »

Then I find that the pH = 6.350.

The answer supposedly has a pH of 6.262.  What did I do wrong?

Your result is correct. BATE gives pH=6.34 and calculation result includes all possible equilibria present in the solution.

Check it by yourself - link to BATE is in my signature, you will have to enter pKa (8.69) manually, as hypobromous acid is not present in the default (demo version) database.
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merced

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Re: find the pH of...
« Reply #3 on: April 27, 2006, 03:44:09 PM »

thanks!
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celestial_kasumi

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Re: find the pH of...
« Reply #4 on: April 30, 2006, 03:31:34 AM »

can i add to this question list?

50ml of HCl 0.0100M added to 50ml 0.0100M NaOH, what is the pH?
thnx
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Alberto_Kravina

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Re: find the pH of...
« Reply #5 on: April 30, 2006, 03:34:15 AM »

Easy. Calculate how much NaCl forms (NaCl is a neutral salt since it is a salt of a strong acid and a strong base). Then you can see if there's an excess NaOH or HCl. Then you can simply calculate the pH with the formula pH= - lg(c0) since NaOH and HCl are both strong a strong base and a stong acid.
But think a bit before caculating and wasting your time...the same volume of a monoprotic base with the same concentration of the acid is added to a monoprotic acid...what could happen ;) ?
« Last Edit: April 30, 2006, 03:36:38 AM by Alberto_Kravina »
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