No such thing as H-, and the product should be - if you are decided to follow my note about CuCl insolubility - CuCl(s). What you wrote doesn't make sense - separate ions are always present only in solution, so they can be only in the (aq) form. So the product on the right is either Cu+(aq) or CuCl(s).
Also note your reaction equation is not balanced. First, you have 1 H on the left, but 2 H on the right. Second, charges don't balance (and they have to, just like atoms). You have -1 on the left and +2 on the right.