[Exploring]

I am looking for information regarding the NaOH-Dioxane mixture, in particular, the fact of “dissolving“ NaOH in dioxane (because both are hygroscopic and it is the water involved who dissolves de NaOH ??), but not sure about the mechanism, and I have no idea about howthe interaction between NaOH-Dioxane is.
I would like to use it to remove trimesic acid and imidazole protons.  It is the NaOH who just take them, and dioxane dissolves the TMA and imidazole molecules?. Besides could dioxane lone pairs of electrons interact with those “removable” protons, and make them more disposed to be removed, or would it be enough just a drop of NaOH to do the job, and dioxane is used just to dissolve the other building blocks in the reaction?
A bit lost here…..thanks for the help