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Topic: What is the result of reacting vinylmagnesium-2-Bromo-1-propen with water (H2O)?  (Read 2795 times)

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Offline carotis

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Someone could help? What is the product from this?
Is it the similiar reaction like Propen with water? I guess not because the O attacks rather the Mg than adding to the C-atom but maybe I am wrong..

Offline Babcock_Hall

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Would you mind drawing out this compound?  I was not able to do so from your description.
« Last Edit: November 23, 2015, 07:01:42 PM by Babcock_Hall »

Offline carotis

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sure thing :D
that's what I've come up with.

Offline beardy

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Grignard reagents are sensitive to water. The active portion is the carbon of the carbon-metal bond. (c-mgbr). When exposed to a proton source (water can act as an acid), carbon essentially deprotonates a proton from water, breaking the c-mgbr bond and forming a new c-h bond. MgBr is now lonely (cation), so it forms an ionic bond to counter the charge with hydroxyl (anion).

Offline beardy

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Rather odd structure, are you sure you copied it correctly?

vinylmagnesium-2-Bromo-1-propen: I think this has a valence error.

Offline carotis

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so... the MgBr-grignard gets away as HO-Mg-Br?

Offline Babcock_Hall

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Grignard reagents are very strong bases.  What happens when a strong base reacts with an acid?

Offline carotis

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An H-atom leaves the carbid. Dimethylpentene would be the product. Hans't that something to do with the Zerewitinow reaction?

Offline Babcock_Hall

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The "H" moiety leaves as a proton.  If we say "atom," it suggests that an electron is also departing (but that is perhaps being a little bit picky).  However, I agree that dimethylpropene would be the product.

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