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Topic: Simple cycloalkane with certain number of Carbons?  (Read 1520 times)

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Offline Oreosftw

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Simple cycloalkane with certain number of Carbons?
« on: November 26, 2015, 07:47:57 PM »
So I'm being asked to draw a structural diagram of two simple cycloalkanes with one methyl group. These two are supposed to be different, just not sure if they're isomers.

Apparently I'm supposed to be drawing the structural formula of a simple C4H8 cycloalkane, and replacing an H atom with methyl, but there's supposed to be 2 different structures that follows these guidelines? How is this possible?

The instructions:
https://gyazo.com/98249ac1e14e5cc7b4bcad3874bafbc1


The table (C4H8 is replaced with just C4, and the same with C5H10, which should be C5)
https://gyazo.com/1a066e91f39e1dc4f8db18de5444b3fb

Thanks for your help.
« Last Edit: November 26, 2015, 08:23:47 PM by Oreosftw »

Offline mjc123

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Re: Simple cycloalkane with certain number of Carbons?
« Reply #1 on: November 27, 2015, 04:38:36 AM »
You aren't asked for isomers. You are asked for (i) a simple cycloalkane C4H8, and (ii) the same, but with one H replaced by a methyl group. There are not two ways of doing this, and you are not asked for two.

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