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Topic: Combustion Analysis Question  (Read 9749 times)

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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #15 on: January 27, 2016, 04:16:20 PM »
How many moles of CO2 , the carbon atoms

There would be 1 mole of C in CO2

Offline AWK

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Re: Combustion Analysis Question
« Reply #16 on: January 27, 2016, 04:18:30 PM »
And in 58,68 g of CO2?
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #17 on: January 27, 2016, 04:26:46 PM »
And in 58,68 g of CO2?

12/44*58.68=16

Offline AWK

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Re: Combustion Analysis Question
« Reply #18 on: January 27, 2016, 04:28:47 PM »
and moles of carbon atoms are?
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #19 on: January 27, 2016, 04:39:36 PM »
and moles of carbon atoms are?

2?
So 2*16=32

Offline AWK

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Re: Combustion Analysis Question
« Reply #20 on: January 27, 2016, 04:40:32 PM »
No!
16 g C - how many moles of C
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #21 on: January 27, 2016, 04:49:13 PM »
No!
16 g C - how many moles of C

So there is only one mole C, ok

Offline AWK

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Re: Combustion Analysis Question
« Reply #22 on: January 27, 2016, 04:52:04 PM »
16/12=1.333
So you have 1.333 mole of C atoms and 2 moles of H atoms ( from 1 mole of H2O).
Could you calculate an empirical formula of this hydrocarbon?
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #23 on: January 27, 2016, 04:54:43 PM »
16/12=1.333

Oh sorry, so the moles of C is 1.333?

Oh! I brainfarted

Offline Burner

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Re: Combustion Analysis Question
« Reply #24 on: January 28, 2016, 01:20:01 AM »
You have '1.333' mole of C and 2 mole of H inside the compund. However, in empirical formula(and most other chemical formulas) the number of atoms must be in whole number. So, what would you do?
Year 1 science student in HKUST and a Chemistry geek.
If I make any mistakes in the forum, please don't hesitate to correct me as I want to learn.

Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #25 on: June 11, 2016, 10:51:01 PM »
Balanced equation : 1 C8H12 + 11 O2  :rarrow: 4 CO2 + 3H2O

Mass of Carbon: 1.44 g
Mass of Hydrogen: 0.18 g
4 moles of Carbon
6 moles of Hydrogen
Empirical Formula: C4H6
Molecular Formula: C8H12

Is this correct?

Offline AWK

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Re: Combustion Analysis Question
« Reply #26 on: June 12, 2016, 01:31:09 AM »
Quote
Balanced equation : 1 C8H12 + 11 O2  :rarrow: 4 CO2 + 3H2O
Balanced?
« Last Edit: June 12, 2016, 06:34:53 AM by Arkcon »
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #27 on: June 12, 2016, 01:43:14 AM »
2 C4H6 + 11 O2  :rarrow: 8 CO2 + 6H2O

whoops

Offline AWK

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Re: Combustion Analysis Question
« Reply #28 on: June 12, 2016, 02:12:28 AM »
Quote
The molar mass of this hydrocarbon is between 50-60 g/mol.
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Offline gigaimpact1

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Re: Combustion Analysis Question
« Reply #29 on: June 14, 2016, 07:55:16 PM »
C4H6 is 54 g/mol.

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