[Baz_UK]

The problem I have here is:

Calculate the concentration of product C and volume of product D using the mass of reactant A dissolved the volume of reactant B 

IE

A(s) + B(aq) = C(aq) +D(g)

or

3Zn(s) + 2H₃PO₄(aq) = Zn₃(PO₄)₂(aq) + 3H₂(g)

when 13.08g of Zn is dissolved in 0.500 dm^-3 of 2H₃PO₄(aq) calculate the concentration of Zn₃(PO₄)₂(aq) and the volume of 3H₂(g)

Thanks

Baz

[AWK]

Something is missing

and show yout work: http://www.chemicalforums.com/index.php?topic=65859.0

[Baz_UK]

I have tried figuring this out and can do everything on the reacts side of the equation, but am having difficulty in translating it to the Products. I'm not looking for the answer, just a bit of help with the method.

Thanks,

Baz

[Arkcon]

You will not figure this out how much products you'll get, until you know how much reactants you've been given, or you've been told you have "reactant in excess."  Specifically:

0.500 dm-3 of 2H₃PO₄(aq)

doesn't tell us how much acid we have, because we don't know how strong it is.

[Baz_UK]

That is all the information given regarding this problem. Maybe something I should bring up with my tutor?

Thanks,
Baz

[sjb]

...doesn't tell us how much acid we have, because we don't know how strong it is.

I think the word you are after is concentrated, not strong. Strong / weak refers more to pKa values.

[Arkcon]

...doesn't tell us how much acid we have, because we don't know how strong it is.

I think the word you are after is concentrated, not strong. Strong / weak refers more to pKa values.

A more correct term, yes.

[AWK]

dissolved in 0.500 dm-³ of 2H₃PO₄(aq)

Concemtration is missing. May be 2M H₃PO₄(aq) is written
(then phosphoric acid is in large excess).