[kensher]

When a complete combustion of methanol happens, you get this reaction:

4NH₃(g) + 7O₂(g)  4NO₂(g) + 6H₂O(l)
ΔH_f(NH₃(g)) = -46,0 kj/mol.

Use the formation of entalphies and figure out the reaction of entalphy. Tables in my book is attached below:


Can anybody share their calculations?

[Corribus]

The way the forum works is that you show your calculations and we tell you how you can improve them (if needed).

[kensher]

Thanks for clarifying
I figured it out eventually (how to solve it correctly).

[Enthalpy]

Sidenotes:
NH₃ is ammonia, not methanol
A natural combustion leaves N₂. NO₂ needs very special conditions.