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Topic: Dissociation of strong base Ca(OH)2?  (Read 2226 times)

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Offline henrybar

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Dissociation of strong base Ca(OH)2?
« on: May 24, 2016, 05:28:00 PM »
 Ca(OH)2(s)--->Ca^2+(aq) +2OH^-(aq)
 Since Ca(OH)2 is a strong base it can be said dissociate 100%, Concentration Ca(OH)2 is 0.0237 M so concentration of OH^- ions is also 0.0237 M but how do I find concentration of Ca^2+ ions? I cannot use ksp values because that is ultimately what im trying to solve for. Ksp=(ca^2+)(0.0237)


Offline Borek

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Re: Dissociation of strong base Ca(OH)2?
« Reply #1 on: May 24, 2016, 06:48:07 PM »
Concentration Ca(OH)2 is 0.0237 M so concentration of OH^- ions is also 0.0237 M

No.

Just look at the stoichiometry of the dissociation. How many moles of OH- produced per every mole of Ca(OH)2 dissociated?
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