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Topic: Benzene and electrons in movement...  (Read 3999 times)

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Offline chocolattes

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Benzene and electrons in movement...
« on: June 23, 2016, 02:42:25 PM »
Hey! First, forgive me for my english, I'm a 18 years old student and I'm about to start college here in Spain :)
I have to do a final project of institute and I was thinking some things about the Benzene.
The component has some resonant bonds.
My question is whether or not the electrons of benzene that are moving generate any radiation or electric current?
I hope i was clear...


Image from https://upload.wikimedia.org/wikipedia/commons/thumb/2/2e/Benzene-2D-full.svg/110px-Benzene-2D-full.svg.png

Offline AWK

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Re: Benzene and electrons in movement...
« Reply #1 on: June 23, 2016, 03:15:03 PM »
Resonance doesn't actually mean that electrons are moving back and forth between the different atoms in benzene ring (unless there's a magnetic field, in which case you get a ring current)

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Offline chocolattes

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Re: Benzene and electrons in movement...
« Reply #2 on: June 23, 2016, 06:24:44 PM »
Thanks!!!
How and how can I look deep into information about this ring current?

Offline AWK

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Re: Benzene and electrons in movement...
« Reply #3 on: June 23, 2016, 07:42:06 PM »
Start from wikipedia: aromatic ring current
and references therein
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Offline Enthalpy

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Re: Benzene and electrons in movement...
« Reply #4 on: June 24, 2016, 10:55:53 AM »
¡Bienvenido, chocolattes! And no worry with your English.

[...] whether or not the electrons of benzene that are moving generate any radiation or electric current? [...]

If the electrons did move, they would indeed radiate an electromagnetic field, for instance light. That was a major problem at the beginning of the 20th century, as physicists modelled atoms by comparison with suns and planets. That the atoms didn't radiate, and the electrons didn't fall on the nucleus, prompted the development of quantum mechanics (QM).

The answer of QM is that electrons don't move (simplifying just some details) when they occupy some "orbitals" in atoms or molecules. Orbitals are called "stationary" for that reason. But the electrons occupy some volume because they are waves rather than points (again simplifying! Everyone agrees with "waves", opinions diverge about "are" - don't go to conflict with your professors about that). Some electrons, let's say the valence electrons (they're slightly more differentiated), take the biggest room, which is the space occupied by the atom or molecule.

In (non excited) benzene too, all electrons are stationary. Each of the six electrons drawn as three doubleD bonds plus resonance and so on sits all the time over the six carbons. So the most accurate symbol is rather c1ccccc1 which keeps the complete symmetry. In fact, drawing any bond between only atom pairs is already an abuse - but it's much more comfortable.

Electrons are not always stationary. Such situations are solutions of Schrödinger's equation for electrons too. For an electron trapped in an atom, a molecule, a region of a semiconductor component... we know that such non-stationary solutions can be written as weighed sums of stationary solutions. And because in such situations, with movement, the electron radiates hences loses energy, they're transitory. After attoseconds to minutes, the formerly excited electron has joined a stationary situation (an "orbital" in the case of an atom or molecule) where it doesn't radiate. This explains why stationary solutions are especially interesting.

QM makes very few assumptions, and uses the same kind of equation for electrons in atoms, in a semiconductor, alone in vacuum... and for other particles. With that, it gives explanations like "why doesn't benzene radiate" and makes numerical predictions that are accurate. As disadvantages, it is sometimes non-intuitive, and its solutions result from computer software except for the simplest situations, but this theory is a Rolls-Royce that represents the world as we observe it, so it is the basis of present physics and chemistry.

Offline chocolattes

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Re: Benzene and electrons in movement...
« Reply #5 on: June 24, 2016, 08:54:47 PM »
Thanks for that answer! :)

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