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Topic: Normality and pH  (Read 3184 times)

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Offline user456

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Normality and pH
« on: July 23, 2016, 02:20:49 AM »
We have to calculate the pH of Ba(OH)2 solution if 10ml of it neutralizes 20ml of 0.01 M HCl solution.
According to law of neutralization-
NAVA=NBVB
20×0.01=10×NB
NB=0.02
After that they calculate the pOH by taking the -logarithm of this normality. But isn't pOH the log of molarity of a base?
also in this case the molarity and normality would be different as there are 2 OH- ions in one Ba(OH)2 molecule.

Offline AWK

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Re: Normality and pH
« Reply #1 on: July 23, 2016, 03:02:42 AM »
Quote
But isn't pOH the log of molarity of a base?
You are right, but base in this case is OH- (normality of Ba(OH)2 = molarity of OH-)
AWK

Offline Babcock_Hall

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Re: Normality and pH
« Reply #2 on: July 23, 2016, 12:53:02 PM »
The formula for pOH needs a minus sign in front of the log, but that's just me being picky.

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