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Topic: Free radical substitution  (Read 1829 times)

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Offline owlpower

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Free radical substitution
« on: October 16, 2016, 09:43:11 AM »
http://imgur.com/EU2LahU

Hi, I have trouble deducing the number of isomers.
I think that there are 2 possible isomers because the presence of the Br will lead to another alkene forming. Apparently there is only 1 isomeric alkene present? Why is it so?
« Last Edit: October 16, 2016, 09:57:33 AM by Arkcon »
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Offline mjc123

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Re: Free radical substitution
« Reply #1 on: October 17, 2016, 04:55:44 AM »
Show the mechanisms by which you think these two alkenes can be formed.
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Offline owlpower

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Re: Free radical substitution
« Reply #2 on: October 20, 2016, 08:09:11 AM »
Hi, here's the mechanism I drew. Here it is : http://imgur.com/5Dc5pw3

I managed to get the same alkene. May I ask why the H atom has to be on the adjacent C atom for elimination reactions though?
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Offline mjc123

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Re: Free radical substitution
« Reply #3 on: October 20, 2016, 08:17:16 AM »
How else do you form a C=C bond?
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