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Topic: Hydrolysis  (Read 2522 times)

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Offline xxdakee

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Hydrolysis
« on: January 11, 2017, 04:43:41 PM »
Al2S3 + 6H2O = 2Al(OH)3 + 3H2S
Can someone explain this reaction to me? Why this is a hydrolysis? And why Al2O3 can't be a product of this reaction instead of Al(OH)3?


I'm 100% sure that this reaction is correct, but I can't find any argument to prove it.

Offline AWK

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Re: Hydrolysis
« Reply #1 on: January 11, 2017, 06:18:14 PM »
Do you know a definition of hydrolysis?
AWK

Offline xxdakee

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Re: Hydrolysis
« Reply #2 on: January 12, 2017, 06:15:32 AM »
Yes I know :)

Offline AWK

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Re: Hydrolysis
« Reply #3 on: January 12, 2017, 06:34:43 AM »
Then this reaction should be obvious.
AWK

Offline xxdakee

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Re: Hydrolysis
« Reply #4 on: January 12, 2017, 06:56:03 AM »
But for my teacher its not lol. She said that the products of this reaction are Al2O3 and H2S

Offline AWK

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Re: Hydrolysis
« Reply #5 on: January 12, 2017, 07:20:28 AM »
When you treat Al2S3 with water vapors at temperature over 400 C then anhydrous Al2O3 is formed. Formation of boehmite (AlOOH) starts about 200 C.
Since Al(OH)3 always contains some water its formula is sometimes written as Al2O3·nH2O. But without H2O below 400 C it is a nonsense.
AWK

Offline xxdakee

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Re: Hydrolysis
« Reply #6 on: January 12, 2017, 08:41:30 AM »
Thanks :) That's all I need :)

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