Synthesis of n-Propyl Propanoate - we distilled/refluxed
Use a graduated cylinder to add the
following pure liquids to a 200 mL distillation
flask:
19.0 mL of n-propanol (0.25 mol)
18.5 mL of propanoic acid (0.25 mol)
Carefully add 5 drops of concentrated sulfuric acid and 2-4 boiling chips.
My questions:
What would the % yield of ester be if the reaction were simply allowed to equilibrate (i.e. no products are removed)?
Compare your experimental % yield of n-propyl propanoate to the predicted equilibrium yield. Were you successful in driving the reaction to the right?
My data:
weight of product= 24.39g
volume of water collected=5.2ml
My calculation of the percent yield=
24.39/4.50 (mass of water) = 5.41% yield of the ester