[candiishop]

Question:

At a constant temperature, 2.00L of O2 gas at an original pressure of 202.6kPa and 3.00L of Ne gas at an original pressure of 303.9 kPa are injected into an evacuated 10.0L container. What pressure is produced inside the container?

The answer is 131.7 kPa

[Albert]

Yes, the answer is correct.

You can use the ideal gas equation to calculate the moles of both gases (T=298K).

[candiishop]

Can u show me how to do it? I mean the working out please Thanks

[Albert]

 

http://wine1.sb.fsu.edu/chm1045/notes/Gases/IdealGas/Gases04.htm

[candiishop]

I still can't get the answer 

P1= 202.6kPa
V1= 2.00L

P2= 303.9kPa
V2= 3.00L

[Albert]

For what concerns oxygen, V=2L and P=202.6kPa. T is 298K, a standard value, when you're not given a different temperature.

Hence, n = (P*V)/(R*T) = moles of oxygen

Do the same for neon.

Then use the sum of the moles of the two gases in the ideal gas law for calculating the final pressure (they give the volume, don't they?).

[Borek]

Alternatlively, calculate pressure for individual gases moved from small tanks to the large one. Pressure of ideal gases is additive.

[candiishop]

Oh i get it. Thank you so much