April 23, 2024, 08:35:06 PM
Forum Rules: Read This Before Posting


Topic: Freundlich adsorption isotherm  (Read 2376 times)

0 Members and 1 Guest are viewing this topic.

Offline ian123

  • Regular Member
  • ***
  • Posts: 26
  • Mole Snacks: +0/-2
Freundlich adsorption isotherm
« on: September 25, 2017, 04:57:48 PM »
Dear Scientists/Engineers,

I would like to ask if my solution to the question is ok because my answers are slightly off to the right answers for K and n. The answers for K = 6.26 in units of conc/conc^(1/n). 1/n = 0.857. Please help me.

Here is my solution

Ceq        lnCeq              Cads           lnCads
20          1.301              80               1.903
120        2.079              380             2.5798
250        2.398              750             2.875
400        2.602              1100           3.041
600        2.778              1400           3.146

Cads = K*Ceq^(1/n)
logCads = (1/n)logCeq + logK
y = mx + c
K=6.43 in units of conc/conc^(1/n)
1/n=0.842

Thanks.

« Last Edit: September 25, 2017, 05:20:35 PM by ian123 »

Sponsored Links