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Topic: Questions on ethers  (Read 2688 times)

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Offline Daiana

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Questions on ethers
« on: January 13, 2018, 12:34:02 PM »
The questions are attached

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Offline Daiana

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Questions on ethers 2
« Reply #1 on: January 13, 2018, 12:35:47 PM »
The questions are attached

Offline Enthalpy

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Re: Questions on ethers
« Reply #2 on: January 14, 2018, 08:23:11 PM »
For (2) it's rather methyl-tert-butyl.

(6) is impossible. A cycle has two hydrogen atoms less than a straight or branched alkane, so it's not an isomer.

The names of dibromo look fine to me.

Offline Daiana

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Re: Questions on ethers
« Reply #3 on: January 16, 2018, 02:50:37 PM »
Thank you a lot! I don't know how to thank you )))
How about 14.44 and that question about 2 squares.

Offline Daiana

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Re: Questions on ethers
« Reply #4 on: January 16, 2018, 02:55:13 PM »
(6) you said that 6 is impossible. However, with CH3 it has the same number of hydrogens like the chains above. I mean that if we took the complete formula - we would get 12 hydrogens.

Offline AdiDex

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Re: Questions on ethers
« Reply #5 on: January 17, 2018, 02:28:55 AM »
You can always use http://www.chemspider.com/FullSearch.aspx for checking IUPAC name.

all you need to do is just draw the structure.

Offline Enthalpy

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Re: Questions on ethers
« Reply #6 on: January 17, 2018, 12:31:18 PM »
(6) has 2*4+1+3=12 hydrogen atoms. As opposed, a straight or ramified ether with 6 carbons has 6*2+2=14 hydrogens.

You don't need to count every hydrogen atom, which is prone to errors. It suffices to know that straight or ramified alkanes have 2*C+2 hydrogens, and that every ring or double bond takes 2*H fewer (triple bonds 4*H, lone benzene rings 8*H etc).

That is, a ring can't be an isomer of a straight alkane. It's an isomer of an alkene.

Imagine that you close a ring from a straight alkane by binding both end C. Each carries 3*H so no bond is possible. Only by removing one H on each C can you make the new C-C bond.

Offline Babcock_Hall

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Re: Questions on ethers
« Reply #7 on: January 17, 2018, 05:47:20 PM »
The use of two squares for a cyclobutyl group may be a misprint of some kind.  I don't recall ever seeing that depiction before.

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