April 23, 2024, 03:40:19 PM
Forum Rules: Read This Before Posting


Topic: Advanced chemistry, energy of bonds!  (Read 1813 times)

0 Members and 1 Guest are viewing this topic.

Offline Bozhyte

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Advanced chemistry, energy of bonds!
« on: January 29, 2018, 11:58:03 AM »
In Plasmid (of 2686 base pairs) in 37 C degrees were found that average of 54.3 base pairs were disengaged/disconnected. Find average energy of one hydrogen bond between base pairs. Do not pay attention to π - π interaction.
The formula I have to use is -kT ln (Q^N)
Q means ratio/proportion of interrupted and formed bonds/connections.
K mans Boltzmann constant.
Sorry for my English, would really appretiate *delete me*

Offline Enthalpy

  • Chemist
  • Sr. Member
  • *
  • Posts: 4041
  • Mole Snacks: +304/-59
Re: Advanced chemistry, energy of bonds!
« Reply #1 on: January 30, 2018, 10:11:24 AM »
Welcome, Bozhyte!

You have a proportion of broken bonds and a temperature. You even have a formula, which is just Boltzmann's distribution slightly rewritten. What are your thoughts?

Boltzmann's distribution tells that even if an event needs more energy than kT, over a big amount of molecules, this event is observed with some frequency, because heat is a mean energy that fluctuates at microscopic scale.

Keep in mind that the small kT relates with molecules and the big RT with moles.

Offline Bozhyte

  • Very New Member
  • *
  • Posts: 2
  • Mole Snacks: +0/-0
Re: Advanced chemistry, energy of bonds!
« Reply #2 on: January 31, 2018, 04:02:16 PM »
Well I am a bit confused cause I did not know if I should use only this 1 formula and I couldnt even find it on the Internet. Also this problem gives 8 points in work which is a lot so thats why im not sure if its the only thing I have to do.
If I understand it correctly, Q is 54.3/2631.7 = 0.021 ?
Not sure about the N

Sponsored Links